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	<title>Comments on: Understanding Linux Load Average &#8211; Part 2</title>
	<atom:link href="http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/feed/" rel="self" type="application/rss+xml" />
	<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/</link>
	<description>By: Harald van Breederode</description>
	<lastBuildDate>Tue, 18 Jun 2013 17:39:13 +0000</lastBuildDate>
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	<item>
		<title>By: Jenny</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-836</link>
		<dc:creator><![CDATA[Jenny]]></dc:creator>
		<pubDate>Wed, 01 May 2013 17:24:31 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-836</guid>
		<description><![CDATA[Hi Harald,

This is very nice article to explain the Load average concept. Thanks for sharing this. But I have question that why on the load average of 4 the number of writing blocks are less than the one on load average of 2. 

Thanks,]]></description>
		<content:encoded><![CDATA[<p>Hi Harald,</p>
<p>This is very nice article to explain the Load average concept. Thanks for sharing this. But I have question that why on the load average of 4 the number of writing blocks are less than the one on load average of 2. </p>
<p>Thanks,</p>
]]></content:encoded>
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	<item>
		<title>By: Understanding Linux CPU Load 资料汇总 &#124; 系统技术非业余研究</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-822</link>
		<dc:creator><![CDATA[Understanding Linux CPU Load 资料汇总 &#124; 系统技术非业余研究]]></dc:creator>
		<pubDate>Fri, 01 Mar 2013 07:54:22 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-822</guid>
		<description><![CDATA[[...] Understanding Linux Load Average 谢谢 @jametong 参考：part1 part2 [...]]]></description>
		<content:encoded><![CDATA[<p>[...] Understanding Linux Load Average 谢谢 @jametong 参考：part1 part2 [...]</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Veritas Volume Manager (VxVM) command line examples &#124; IT World</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-715</link>
		<dc:creator><![CDATA[Veritas Volume Manager (VxVM) command line examples &#124; IT World]]></dc:creator>
		<pubDate>Mon, 16 Jul 2012 09:54:42 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-715</guid>
		<description><![CDATA[[...] Understanding Linux Load Average – Part 2 [...]]]></description>
		<content:encoded><![CDATA[<p>[...] Understanding Linux Load Average – Part 2 [...]</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Raheel Syed</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-673</link>
		<dc:creator><![CDATA[Raheel Syed]]></dc:creator>
		<pubDate>Tue, 15 May 2012 14:42:11 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-673</guid>
		<description><![CDATA[Reblogged this on &lt;a href=&quot;http://raheeldba.wordpress.com/2012/05/15/106/&quot; rel=&quot;nofollow&quot;&gt;Raheel&#039;s Blog&lt;/a&gt; and commented: 
Interesting series Part 2: Understanding Linux Load Average]]></description>
		<content:encoded><![CDATA[<p>Reblogged this on <a href="http://raheeldba.wordpress.com/2012/05/15/106/" rel="nofollow">Raheel&#039;s Blog</a> and commented:<br />
Interesting series Part 2: Understanding Linux Load Average</p>
]]></content:encoded>
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	<item>
		<title>By: Harald van Breederode</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-665</link>
		<dc:creator><![CDATA[Harald van Breederode]]></dc:creator>
		<pubDate>Thu, 10 May 2012 11:46:15 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-665</guid>
		<description><![CDATA[Hi Izzol,

Thanx for your constructive feedback ...
-Harald]]></description>
		<content:encoded><![CDATA[<p>Hi Izzol,</p>
<p>Thanx for your constructive feedback &#8230;<br />
-Harald</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: izzol</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-664</link>
		<dc:creator><![CDATA[izzol]]></dc:creator>
		<pubDate>Thu, 10 May 2012 08:17:54 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-664</guid>
		<description><![CDATA[Because the Linux Scheduler is fuckup :) Try the same on FreBSD for example :)]]></description>
		<content:encoded><![CDATA[<p>Because the Linux Scheduler is fuckup :) Try the same on FreBSD for example :)</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Harald van Breederode</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-658</link>
		<dc:creator><![CDATA[Harald van Breederode]]></dc:creator>
		<pubDate>Mon, 07 May 2012 08:42:37 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-658</guid>
		<description><![CDATA[Hi Marco,

The dd processes generating the disk I/O are driven by a shell script similar to:
while :
  dd of=file.$$ ...
  rm file.$$
done
So there are actually 4 processes involvedduring the first experiment, which explains why the run-queue utilization varies between 1 and 4.]]></description>
		<content:encoded><![CDATA[<p>Hi Marco,</p>
<p>The dd processes generating the disk I/O are driven by a shell script similar to:<br />
while :<br />
  dd of=file.$$ &#8230;<br />
  rm file.$$<br />
done<br />
So there are actually 4 processes involvedduring the first experiment, which explains why the run-queue utilization varies between 1 and 4.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Admin</title>
		<link>http://prutser.wordpress.com/2012/05/05/understanding-linux-load-average-part-2/#comment-656</link>
		<dc:creator><![CDATA[Admin]]></dc:creator>
		<pubDate>Sun, 06 May 2012 10:43:03 +0000</pubDate>
		<guid isPermaLink="false">http://prutser.wordpress.com/?p=732#comment-656</guid>
		<description><![CDATA[Hi Harald,

Thanks for the nice topic. I have two findings. The first is that, while running only the two processes performing disk I/O, the sar output shows the runq-sz varying from 1 to 4. I should expect max 2 processes on the run queue.

The second is that, while running both the cpu and I/O bound scripts, the runq-sz is constantly on 4 processes on the run queue. So the I/O based processes seem to be on the run queue all the time

Best regards,
Marco]]></description>
		<content:encoded><![CDATA[<p>Hi Harald,</p>
<p>Thanks for the nice topic. I have two findings. The first is that, while running only the two processes performing disk I/O, the sar output shows the runq-sz varying from 1 to 4. I should expect max 2 processes on the run queue.</p>
<p>The second is that, while running both the cpu and I/O bound scripts, the runq-sz is constantly on 4 processes on the run queue. So the I/O based processes seem to be on the run queue all the time</p>
<p>Best regards,<br />
Marco</p>
]]></content:encoded>
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